Reverse Words in a String III
As a Systems Engineer at Tata Consultancy Services, I deliver exceptional software products for mobile and web platforms, using agile methodologies and robust quality maintenance. I am experienced in performance testing, automation testing, API testing, and manual testing, with various tools and technologies such as Jmeter, Azure LoadTest, Selenium, Java, OOPS, Maven, TestNG, and Postman.
I have successfully developed and executed detailed test plans, test cases, and scripts for Android and web applications, ensuring high-quality standards and user satisfaction. I have also demonstrated my proficiency in manual REST API testing with Postman, as well as in end-to-end performance and automation testing using Jmeter and selenium with Java, TestNG and Maven. Additionally, I have utilized Azure DevOps for bug tracking and issue management.
Given a string s, reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order.
LeetCode Problem - 557: Link | Click Here
class Solution {
public String reverseWords(String s) {
// StringBuilder to store the reversed words
StringBuilder sb1 = new StringBuilder();
// Split the input string into an array of words
String[] splitString = s.split(" ");
// Iterate through each word in the array
for (int i=0; i<splitString.length; i++){
// Reverse the current word
String reverseChar = reverseChar(splitString[i]);
// Append the reversed word to the StringBuilder
if (i==(splitString.length-1)){
// If it's the last word, append without space
sb1.append(reverseChar);
}
else {
// If not the last word, append with a space
sb1.append(reverseChar).append(" ");
}
}
// Convert the StringBuilder to a string and return
return sb1.toString();
}
// Function to reverse a given string
static String reverseChar(String c){
// StringBuilder to store the reversed string
StringBuilder sb2 = new StringBuilder();
// Iterate through each character in the string in reverse order
for (int i=c.length()-1; i>=0; i--){
// Append the current character to the StringBuilder
sb2.append(c.charAt(i));
}
// Convert the StringBuilder to a string and return
return sb2.toString();
}
}
