Find the Length of the Longest Common Prefix

As a Systems Engineer at Tata Consultancy Services, I deliver exceptional software products for mobile and web platforms, using agile methodologies and robust quality maintenance. I am experienced in performance testing, automation testing, API testing, and manual testing, with various tools and technologies such as Jmeter, Azure LoadTest, Selenium, Java, OOPS, Maven, TestNG, and Postman.
I have successfully developed and executed detailed test plans, test cases, and scripts for Android and web applications, ensuring high-quality standards and user satisfaction. I have also demonstrated my proficiency in manual REST API testing with Postman, as well as in end-to-end performance and automation testing using Jmeter and selenium with Java, TestNG and Maven. Additionally, I have utilized Azure DevOps for bug tracking and issue management.
You are given two arrays with positive integers arr1 and arr2.
A prefix of a positive integer is an integer formed by one or more of its digits, starting from its leftmost digit. For example, 123 is a prefix of the integer 12345, while 234 is not.
A common prefix of two integers a and b is an integer c, such that c is a prefix of both a and b. For example, 5655359 and 56554 have a common prefix 565 while 1223 and 43456 do not have a common prefix.
You need to find the length of the longest common prefix between all pairs of integers (x, y) such that x belongs to arr1 and y belongs to arr2.
Return the length of the longest common prefix among all pairs. If no common prefix exists among them, return 0.
LeetCode Problem - 3043
class Solution {
public int longestCommonPrefix(int[] arr1, int[] arr2) {
// Set to store unique digits present in the elements of arr1.
Set<Integer> prefix = new HashSet<>();
// Loop through arr1 elements to extract digits and add them to the set.
for (int i : arr1){
while (i > 0){
prefix.add(i % 10); // Extracting and adding each digit.
i /= 10; // Move to the next digit.
}
}
int result = 0; // Variable to store the length of the longest common prefix.
// Loop through arr2 elements to find the common digits.
for (int i : arr2){
while (i > 0){
if (prefix.contains(i)){ // If the digit is present in the set.
result = Math.max(result, numLen(i)); // Update the result with maximum length.
}
i /= 10; // Move to the next digit.
}
}
return result; // Return the length of the longest common prefix.
}
// Function to find the length of a number.
private int numLen(int num){
return String.valueOf(num).length(); // Convert the number to a string and return its length.
}
}




