XOR Operation in an Array
As a Systems Engineer at Tata Consultancy Services, I deliver exceptional software products for mobile and web platforms, using agile methodologies and robust quality maintenance. I am experienced in performance testing, automation testing, API testing, and manual testing, with various tools and technologies such as Jmeter, Azure LoadTest, Selenium, Java, OOPS, Maven, TestNG, and Postman.
I have successfully developed and executed detailed test plans, test cases, and scripts for Android and web applications, ensuring high-quality standards and user satisfaction. I have also demonstrated my proficiency in manual REST API testing with Postman, as well as in end-to-end performance and automation testing using Jmeter and selenium with Java, TestNG and Maven. Additionally, I have utilized Azure DevOps for bug tracking and issue management.
You are given an integer n and an integer start.
Define an array nums where nums[i] = start + 2 * i (0-indexed) and n == nums.length.
Return the bitwise XOR of all elements of nums.
LeetCode Problem - 1486
class Solution {
public int xorOperation(int n, int start) {
// Initialize the result of XOR operations
int answer = 0;
// Iterate through the range of n
for (int i = 0; i < n; i++) {
// Perform XOR operation with the current element in the sequence
answer ^= start + 2 * i;
}
// Return the final result after all XOR operations
return answer;
}
}
