Richest Customer Wealth

As a Systems Engineer at Tata Consultancy Services, I deliver exceptional software products for mobile and web platforms, using agile methodologies and robust quality maintenance. I am experienced in performance testing, automation testing, API testing, and manual testing, with various tools and technologies such as Jmeter, Azure LoadTest, Selenium, Java, OOPS, Maven, TestNG, and Postman.
I have successfully developed and executed detailed test plans, test cases, and scripts for Android and web applications, ensuring high-quality standards and user satisfaction. I have also demonstrated my proficiency in manual REST API testing with Postman, as well as in end-to-end performance and automation testing using Jmeter and selenium with Java, TestNG and Maven. Additionally, I have utilized Azure DevOps for bug tracking and issue management.
You are given an m x n integer grid accounts where accounts[i][j] is the amount of money the i<sup>th</sup> customer has in the j<sup>th</sup> bank. Return the wealth that the richest customer has.
A customer's wealth is the amount of money they have in all their bank accounts. The richest customer is the customer that has the maximum wealth.
LeetCode Problem - 1672
class Solution {
public int maximumWealth(int[][] accounts) {
// Initialize a variable 'maxVal' to keep track of the maximum wealth found.
int maxVal = 0;
// Iterate through each 'account' in the 'accounts' array.
for (int[] account : accounts) {
// Initialize a temporary variable 'temp' to store the sum of wealth for the current customer.
int temp = 0;
// Iterate through each element 'j' in the 'account'.
for (int j = 0; j < accounts[0].length; j++) {
// Add the wealth at index 'j' to the 'temp' variable.
temp += account[j];
}
// Check if the wealth of the current customer ('temp') is greater than the current maximum wealth ('maxVal').
// If so, update 'maxVal' to the wealth of the current customer.
if (temp > maxVal) {
maxVal = temp;
}
}
// Return the maximum wealth among all the customers.
return maxVal;
}
}




