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Remove Duplicates from Sorted List

Published
2 min read
Remove Duplicates from Sorted List
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As a Systems Engineer at Tata Consultancy Services, I deliver exceptional software products for mobile and web platforms, using agile methodologies and robust quality maintenance. I am experienced in performance testing, automation testing, API testing, and manual testing, with various tools and technologies such as Jmeter, Azure LoadTest, Selenium, Java, OOPS, Maven, TestNG, and Postman.

I have successfully developed and executed detailed test plans, test cases, and scripts for Android and web applications, ensuring high-quality standards and user satisfaction. I have also demonstrated my proficiency in manual REST API testing with Postman, as well as in end-to-end performance and automation testing using Jmeter and selenium with Java, TestNG and Maven. Additionally, I have utilized Azure DevOps for bug tracking and issue management.

Given the head of a sorted linked list, delete all duplicates such that each element appears only once. Return the linked list sorted as well.

LeetCode Problem - 83

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;        // value of the node
 *     ListNode next;  // reference to the next node in the list
 *     ListNode() {}   // default constructor
 *     ListNode(int val) { this.val = val; }  // constructor with value only
 *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }  // constructor with value and next node
 * }
 */
class Solution {
    // Method to remove duplicates from a sorted linked list
    public ListNode deleteDuplicates(ListNode head) {
        // If the list is empty, return null
        if (head == null) return null;

        // Pointer to the current node being checked
        ListNode current = head;

        // Traverse the linked list
        while (current != null && current.next != null) {
            // If the current node's value is the same as the next node's value
            if (current.val == current.next.val) {
                // Skip the next node by changing the next pointer
                current.next = current.next.next;
            } else {
                // Move to the next node if no duplicate is found
                current = current.next;
            }
        }

        // Return the head of the modified list (with duplicates removed)
        return head;
    }
}

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Remove Duplicates from Sorted List