N-Repeated Element in Size 2N Array

As a Systems Engineer at Tata Consultancy Services, I deliver exceptional software products for mobile and web platforms, using agile methodologies and robust quality maintenance. I am experienced in performance testing, automation testing, API testing, and manual testing, with various tools and technologies such as Jmeter, Azure LoadTest, Selenium, Java, OOPS, Maven, TestNG, and Postman.
I have successfully developed and executed detailed test plans, test cases, and scripts for Android and web applications, ensuring high-quality standards and user satisfaction. I have also demonstrated my proficiency in manual REST API testing with Postman, as well as in end-to-end performance and automation testing using Jmeter and selenium with Java, TestNG and Maven. Additionally, I have utilized Azure DevOps for bug tracking and issue management.
You are given an integer array nums with the following properties:
nums.length == 2 * n.numscontainsn + 1unique elements.Exactly one element of
numsis repeatedntimes.
Return the element that is repeated n times.
LeetCode Problem - 961
class Solution {
public int repeatedNTimes(int[] nums) {
// Create a HashSet to keep track of seen elements
Set<Integer> set = new HashSet<>();
// Iterate through each element in the nums array
for (int ele : nums) {
// Check if the current element is already in the set
if (set.contains(ele)) {
// If it is, this is the repeated element, return it
return ele;
}
// Otherwise, add the current element to the set
set.add(ele);
}
// Return -1 if no repeated element is found (shouldn't happen per problem statement)
return -1;
}
}




