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N-Repeated Element in Size 2N Array

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N-Repeated Element in Size 2N Array
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As a Systems Engineer at Tata Consultancy Services, I deliver exceptional software products for mobile and web platforms, using agile methodologies and robust quality maintenance. I am experienced in performance testing, automation testing, API testing, and manual testing, with various tools and technologies such as Jmeter, Azure LoadTest, Selenium, Java, OOPS, Maven, TestNG, and Postman.

I have successfully developed and executed detailed test plans, test cases, and scripts for Android and web applications, ensuring high-quality standards and user satisfaction. I have also demonstrated my proficiency in manual REST API testing with Postman, as well as in end-to-end performance and automation testing using Jmeter and selenium with Java, TestNG and Maven. Additionally, I have utilized Azure DevOps for bug tracking and issue management.

You are given an integer array nums with the following properties:

  • nums.length == 2 * n.

  • nums contains n + 1 unique elements.

  • Exactly one element of nums is repeated n times.

Return the element that is repeated n times.

LeetCode Problem - 961

class Solution {
    public int repeatedNTimes(int[] nums) {
        // Create a HashSet to keep track of seen elements
        Set<Integer> set = new HashSet<>();

        // Iterate through each element in the nums array
        for (int ele : nums) {
            // Check if the current element is already in the set
            if (set.contains(ele)) {
                // If it is, this is the repeated element, return it
                return ele;
            }
            // Otherwise, add the current element to the set
            set.add(ele);
        } 

        // Return -1 if no repeated element is found (shouldn't happen per problem statement)
        return -1;
    }
}

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