Modify the Matrix
As a Systems Engineer at Tata Consultancy Services, I deliver exceptional software products for mobile and web platforms, using agile methodologies and robust quality maintenance. I am experienced in performance testing, automation testing, API testing, and manual testing, with various tools and technologies such as Jmeter, Azure LoadTest, Selenium, Java, OOPS, Maven, TestNG, and Postman.
I have successfully developed and executed detailed test plans, test cases, and scripts for Android and web applications, ensuring high-quality standards and user satisfaction. I have also demonstrated my proficiency in manual REST API testing with Postman, as well as in end-to-end performance and automation testing using Jmeter and selenium with Java, TestNG and Maven. Additionally, I have utilized Azure DevOps for bug tracking and issue management.
Given a 0-indexed m x n integer matrix matrix, create a new 0-indexed matrix called answer. Make answer equal to matrix, then replace each element with the value -1 with the maximum element in its respective column.
Return the matrix answer.
LeetCode Problem - 3033
class Solution {
// Method to modify the matrix based on specific rules
public int[][] modifiedMatrix(int[][] matrix) {
// Loop through each row of the matrix
for (int i = 0; i < matrix.length; i++) {
// Loop through each column in the current row
for (int j = 0; j < matrix[0].length; j++) {
// If the current element is -1, replace it with the largest element in the same column
if (matrix[i][j] == -1) {
matrix[i][j] = largestElement(j, matrix);
}
}
}
// Return the modified matrix
return matrix;
}
// Method to find the largest element in a given column
public int largestElement(int col, int[][] matrix) {
// Initialize the result with the smallest possible integer value
int result = Integer.MIN_VALUE;
// Loop through each row of the matrix to find the largest element in the specified column
for (int i = 0; i < matrix.length; i++) {
int currVal = matrix[i][col];
// Update the result if the current value is larger than the existing largest value
if (currVal > result) {
result = currVal;
}
}
// Return the largest element found in the column
return result;
}
}
