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Increasing Decreasing String

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2 min read
Increasing Decreasing String
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As a Systems Engineer at Tata Consultancy Services, I deliver exceptional software products for mobile and web platforms, using agile methodologies and robust quality maintenance. I am experienced in performance testing, automation testing, API testing, and manual testing, with various tools and technologies such as Jmeter, Azure LoadTest, Selenium, Java, OOPS, Maven, TestNG, and Postman.

I have successfully developed and executed detailed test plans, test cases, and scripts for Android and web applications, ensuring high-quality standards and user satisfaction. I have also demonstrated my proficiency in manual REST API testing with Postman, as well as in end-to-end performance and automation testing using Jmeter and selenium with Java, TestNG and Maven. Additionally, I have utilized Azure DevOps for bug tracking and issue management.

You are given a string s. Reorder the string using the following algorithm:

  1. Pick the smallest character from s and append it to the result.

  2. Pick the smallest character from s which is greater than the last appended character to the result and append it.

  3. Repeat step 2 until you cannot pick more characters.

  4. Pick the largest character from s and append it to the result.

  5. Pick the largest character from s which is smaller than the last appended character to the result and append it.

  6. Repeat step 5 until you cannot pick more characters.

  7. Repeat the steps from 1 to 6 until you pick all characters from s.

In each step, If the smallest or the largest character appears more than once you can choose any occurrence and append it to the result.

Return the result string after sorting s with this algorithm.

LeetCode Problem - 1370

class Solution {
    // Function to sort a string in ascending and descending order of characters alternately
    public String sortString(String s) {

        // Map to store character frequencies
        Map<Character, Integer> map = new HashMap<>();
        // Count the frequency of each character
        for(char c : s.toCharArray()){
            map.put(c, map.getOrDefault(c, 0)+1);
        }

        // StringBuilder to store the sorted string
        StringBuilder sb = new StringBuilder();
        // Loop until all characters are processed
        while(!map.isEmpty()){
            try{
                // Sort characters in ascending order
                Set<Character> keySet = map.keySet();
                List<Character> keyList = new ArrayList<>(keySet);
                Collections.sort(keyList);
                // Append characters in ascending order to the result string
                for(char c : keyList){
                    sb.append(c);
                    map.put(c, map.getOrDefault(c, 0)-1);
                    // Remove the character if its frequency becomes 0
                    if (map.get(c) == 0){
                        map.remove(c);
                    }
                }

                // Sort characters in descending order
                Set<Character> keySet2 = map.keySet();
                List<Character> keyList2 = new ArrayList<>(keySet2);
                Collections.sort(keyList2, Collections.reverseOrder());
                // Append characters in descending order to the result string
                for(char c : keyList2){
                    sb.append(c);
                    map.put(c, map.getOrDefault(c, 0)-1);
                    // Remove the character if its frequency becomes 0
                    if (map.get(c) == 0){
                        map.remove(c);
                    }
                }
            } catch (Exception e){
                // Continue to the next iteration if an exception occurs (e.g., ConcurrentModificationException)
                continue;
            }
        }
        // Return the sorted string
        return sb.toString();
    }
}

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