Happy Number

As a Systems Engineer at Tata Consultancy Services, I deliver exceptional software products for mobile and web platforms, using agile methodologies and robust quality maintenance. I am experienced in performance testing, automation testing, API testing, and manual testing, with various tools and technologies such as Jmeter, Azure LoadTest, Selenium, Java, OOPS, Maven, TestNG, and Postman.
I have successfully developed and executed detailed test plans, test cases, and scripts for Android and web applications, ensuring high-quality standards and user satisfaction. I have also demonstrated my proficiency in manual REST API testing with Postman, as well as in end-to-end performance and automation testing using Jmeter and selenium with Java, TestNG and Maven. Additionally, I have utilized Azure DevOps for bug tracking and issue management.
Write an algorithm to determine if a number n is happy.
A happy number is a number defined by the following process:
Starting with any positive integer, replace the number by the sum of the squares of its digits.
Repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1.
Those numbers for which this process ends in 1 are happy.
Return true if n is a happy number, and false if not.
LeetCode Problem - 202
class Solution {
public boolean isHappy(int n) {
// Set to keep track of the numbers we've seen to detect cycles
Set<Integer> seen = new HashSet<>();
// Continue the process until n becomes 1 or we see a repeated number (cycle detection)
while (n != 1 && !seen.contains(n)) {
seen.add(n); // Add the current number to the set of seen numbers
n = digitSum(n); // Update n to the sum of the squares of its digits
}
// Return true if n is 1 (happy number), otherwise false (not a happy number)
return n == 1;
}
// Helper method to calculate the sum of the squares of the digits of a number
private int digitSum(int num) {
int sum = 0;
// Process each digit of the number
while (num != 0) {
int digit = num % 10; // Extract the last digit of num
sum += digit * digit; // Add the square of the digit to sum
num /= 10; // Remove the last digit from num
}
return sum; // Return the calculated sum
}
}




