First Unique Character in a String
As a Systems Engineer at Tata Consultancy Services, I deliver exceptional software products for mobile and web platforms, using agile methodologies and robust quality maintenance. I am experienced in performance testing, automation testing, API testing, and manual testing, with various tools and technologies such as Jmeter, Azure LoadTest, Selenium, Java, OOPS, Maven, TestNG, and Postman.
I have successfully developed and executed detailed test plans, test cases, and scripts for Android and web applications, ensuring high-quality standards and user satisfaction. I have also demonstrated my proficiency in manual REST API testing with Postman, as well as in end-to-end performance and automation testing using Jmeter and selenium with Java, TestNG and Maven. Additionally, I have utilized Azure DevOps for bug tracking and issue management.
Given a string s, find the first non-repeating character in it and return its index. If it does not exist, return -1.
LeetCode Problem - 387
class Solution {
// This method finds the index of the first unique character in a string.
public int firstUniqChar(String s) {
// Convert the string to a character array.
char[] c = s.toCharArray();
// Iterate through the characters of the string.
for (int i = 0; i < s.length(); i++) {
// Initialize a count variable to count occurrences of the current character.
int count = 0;
// Iterate through the characters of the string again to compare with the current character.
for (char currentChar : c) {
// If the current character matches the character at index i, increment the count.
if (currentChar == (s.charAt(i))) {
count++;
}
// If the count exceeds 1, break the loop as the character is not unique.
if (count > 1) {
break;
}
}
// If the count is 1, return the index of the first unique character.
if (count == 1) {
return i;
}
}
// If no unique character is found, return -1.
return -1;
}
}
