Find the Town Judge

As a Systems Engineer at Tata Consultancy Services, I deliver exceptional software products for mobile and web platforms, using agile methodologies and robust quality maintenance. I am experienced in performance testing, automation testing, API testing, and manual testing, with various tools and technologies such as Jmeter, Azure LoadTest, Selenium, Java, OOPS, Maven, TestNG, and Postman.
I have successfully developed and executed detailed test plans, test cases, and scripts for Android and web applications, ensuring high-quality standards and user satisfaction. I have also demonstrated my proficiency in manual REST API testing with Postman, as well as in end-to-end performance and automation testing using Jmeter and selenium with Java, TestNG and Maven. Additionally, I have utilized Azure DevOps for bug tracking and issue management.
In a town, there are n people labeled from 1 to n. There is a rumor that one of these people is secretly the town judge.
If the town judge exists, then:
The town judge trusts nobody.
Everybody (except for the town judge) trusts the town judge.
There is exactly one person that satisfies properties 1 and 2.
You are given an array trust where trust[i] = [a<sub>i</sub>, b<sub>i</sub>] representing that the person labeled a<sub>i</sub> trusts the person labeled b<sub>i</sub>. If a trust relationship does not exist in trust array, then such a trust relationship does not exist.
Return the label of the town judge if the town judge exists and can be identified, or return -1 otherwise.
LeetCode Problem - 997
class Solution {
public int findJudge(int n, int[][] trust){
// Create an array to store the count of trusts for each person.
int[] count = new int[n+1];
// Iterate through the trust relationships.
for (int[] t : trust){
// Decrement the count for the person making the trust.
count[t[0]]--;
// Increment the count for the person being trusted.
count[t[1]]++;
}
// Iterate through the people in the town.
for (int i = 1; i<=n; i++){
// If a person's trust count equals 'n-1', they are the judge.
if (count[i]==n-1)
return i;
}
// If no judge is found, return -1.
return -1;
}
}




