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Excel Sheet Column Title

Published
1 min read
Excel Sheet Column Title
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As a Systems Engineer at Tata Consultancy Services, I deliver exceptional software products for mobile and web platforms, using agile methodologies and robust quality maintenance. I am experienced in performance testing, automation testing, API testing, and manual testing, with various tools and technologies such as Jmeter, Azure LoadTest, Selenium, Java, OOPS, Maven, TestNG, and Postman.

I have successfully developed and executed detailed test plans, test cases, and scripts for Android and web applications, ensuring high-quality standards and user satisfaction. I have also demonstrated my proficiency in manual REST API testing with Postman, as well as in end-to-end performance and automation testing using Jmeter and selenium with Java, TestNG and Maven. Additionally, I have utilized Azure DevOps for bug tracking and issue management.

Given an integer columnNumber, return its corresponding column title as it appears in an Excel sheet.

For example:

A -> 1
B -> 2
C -> 3
...
Z -> 26
AA -> 27
AB -> 28 
...

LeetCode Problem - 168

class Solution {
    public String convertToTitle(int columnNumber) {
        // Initialize a StringBuilder to store the resulting column title
        StringBuilder sb = new StringBuilder();

        // Loop until the entire column number is processed
        while (columnNumber > 0) {
            // Calculate the remainder when columnNumber is divided by 26
            // Subtract 1 because the alphabet is 1-based (A=1, B=2, ..., Z=26)
            int remainder = (columnNumber - 1) % 26;

            // Convert the remainder to the corresponding alphabet character
            // Add 'A' to align the remainder with the ASCII value of 'A'
            sb.append((char) (remainder + 'A'));

            // Update columnNumber for the next iteration by dividing it by 26
            // Subtract 1 to maintain the correct alignment with the alphabet
            columnNumber = (columnNumber - 1) / 26;
        }

        // The result is in reverse order, so reverse it before returning
        return sb.reverse().toString();
    }
}

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