Determine if String Halves Are Alike
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You are given a string s of even length. Split this string into two halves of equal lengths, and let a be the first half and b be the second half.
Two strings are alike if they have the same number of vowels ('a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'). Notice that s contains uppercase and lowercase letters.
Return true if a and b are alike. Otherwise, return false.
LeetCode Problem: Link | Click Here
import java.util.ArrayList;
class Solution {
public boolean halvesAreAlike(String s) {
// Calculate the index to split the string into two halves
int splitStr = s.length() / 2;
boolean result = false;
// Create an ArrayList to store vowels
ArrayList<Character> vowels = new ArrayList<>();
vowels.add('a'); vowels.add('e'); vowels.add('i'); vowels.add('o'); vowels.add('u');
vowels.add('A'); vowels.add('E'); vowels.add('I'); vowels.add('O'); vowels.add('U');
// Extract the first half of the string
String a = s.substring(0, splitStr);
// Extract the second half of the string
String b = s.substring(splitStr);
// Count the number of vowels in each half
int aa = vowelsCount(a, vowels);
int bb = vowelsCount(b, vowels);
// Check if the counts of vowels in both halves are equal
if (aa == bb) {
result = true;
}
return result;
}
// Method to count the number of vowels in a given string
public int vowelsCount(String s, ArrayList<Character> vowels) {
int count = 0;
// Iterate through the characters of the string
for (int i = 0; i < s.length(); i++) {
// Check if the character is a vowel
if (vowels.contains(s.charAt(i))) {
count++;
}
}
return count;
}
}
